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Alk:
Hello , if you please..
can you explain to me , how to solve Q 2 (c)  P3 October/November 2005?
thank you very much

astarmathsandphysics:
This shows how to find the nth term for a cubic sequence.

4 15 44 103 204
1st diff 11 29 59 101
2nd diff 18 30 42
3rd diff 12 12 so 12/6=2 It is a   sequence

Do a line 2 16 54 128 250

Take this away from the original sequence

2 -1 -10 -25 -46

This is  a quadratic sequence
1st diff -3 -9 -15 -21
2nd diff -6 -6 -6 -6 -6/2=-3

Do a line -3 -12 -27 -48

Take this away from the quadratic sequence 5 11 17 23. This is linear, the difference is 6 so it is a 6n-1 sequence and the complete rule is

SGVaibhav:
thanx buddy

sweetsh:
Teacher  ;)

The file is not opening  ???

Im wondering.....?

astarmathsandphysics:
Which file doesn't open?

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