Author Topic: Maths & Physics Help  (Read 59901 times)

Offline shivluvchem

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Re: Maths & Physics Help
« Reply #30 on: November 02, 2008, 10:05:08 pm »
We dont have log in our sylabus!
And the ans is not 1 it is 0!
It says in the marking scheme!

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #31 on: November 02, 2008, 10:10:37 pm »
f(x)=log10x
and f-1(x)=10^x
so if you start with 1, you get log1=0 then 10^0=1, but it is irrelevant. It is just to do with f and f-1. You wnd up with the thing you started with
« Last Edit: November 02, 2008, 10:12:19 pm by astarmathsandphysics »

Offline shivluvchem

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Re: Maths & Physics Help
« Reply #32 on: November 02, 2008, 10:14:42 pm »
Sorry but i didn't understand!

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #33 on: November 02, 2008, 10:18:55 pm »
Think of powers. x^2*x^-2=1
but but f(f-1(x))=x
an inverse to f undoes f so you end up with what you started.

Offline igvictim

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Re: Maths & Physics Help
« Reply #34 on: November 02, 2008, 11:23:14 pm »
Hi,

I am about to have my science paper 3 IG very soon, and I was wondering which are the most common physics equations that appear in this paper.

thank you

Offline xygoninator

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Re: Maths & Physics Help
« Reply #35 on: November 03, 2008, 03:12:34 am »
huh? shouldn't it be 1 root 10? and the answer without log should be 3.16?

Offline shivluvchem

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Re: Maths & Physics Help
« Reply #36 on: November 03, 2008, 03:20:15 am »
xactlie...
Its a question frm nov 2005...ppr 2!
Im confused!!Help!!!!

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #37 on: November 03, 2008, 06:09:02 am »
here is a forula sheet

Offline igvictim

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Re: Maths & Physics Help
« Reply #38 on: November 03, 2008, 06:20:38 am »
sorry but, how I open it? it is a DOS app

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #39 on: November 03, 2008, 06:40:55 am »
try this

sonali

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Re: Maths & Physics Help
« Reply #40 on: November 03, 2008, 07:53:16 am »
hey this is seriosly tough
plzz crack this fr me
plzz give full details oh hw to get to d ans
q. when each edge of a cube is decreased by 1cm, its volume is decreased by 91cm^3 (i mean 91cm cube). find the lenghth of d side of d original cube.
u hv to form eq n solve this

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #41 on: November 03, 2008, 08:12:11 am »
orig volume=x^3
new volume=(x-1)^3=x^3-3x^2+3x-1
equation is x^3-(x^3-3x^2+3x-1)=91
ie 3x^2-3x+1=91
3x^2-3x-90=0
x^2-x-30=0
(x-6)(x+5)=0
x=6 or -5
but it must be 6 since x must be positive.

Offline badboy

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Re: Maths & Physics Help
« Reply #42 on: November 03, 2008, 10:23:39 am »
yoo pipo am duin maths paper 2 extended on 5th november can any 1 help with questions of maths  n also chemistry and physics

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #43 on: November 03, 2008, 10:30:22 am »
post questions here and i will help. for some to do goto www.freexampapers.com

Offline badboy

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Re: Maths & Physics Help
« Reply #44 on: November 03, 2008, 11:29:28 am »
yo astarinmaths n physics cum onlin ive added u in msn hotmail