Author Topic: Maths & Physics Help  (Read 17550 times)

Offline toobeerajpanchoo

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Re: Maths & Physics Help
« Reply #30 on: October 24, 2009, 12:15:17 pm »
HEY | am | I WANNA KNOW HOW U DO TO CALCULATE AREA UNDER GRAPH ALL ITS FORMULAS

Offline Ghost Of Highbury

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Re: Maths & Physics Help
« Reply #31 on: October 24, 2009, 12:23:07 pm »
HEY | am | I WANNA KNOW HOW U DO TO CALCULATE AREA UNDER GRAPH ALL ITS FORMULAS

if its a speed-time graph...the area under the graph would be the distance covered.

Theres no formula to find it, u have to first identify the shape. It can be a trapezium/square/triangle anything..

find a sample graph below and i have shown how u calculate the area under the graph..

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first identify the shape - trapezium

area of trapezium = 0.5 * (sum of parallel sides) * perpendicuar height = 0.5 * (7+10) * 25 = 212.5cm2

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u can also use integration to find the area.

divine intervention!

Offline toobeerajpanchoo

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Re: Maths & Physics Help
« Reply #32 on: October 24, 2009, 01:03:22 pm »
ALRIGHT I UNDERSTOOD BUT COULD EXPLAIN HOW TO DO THE QUESTIONS IN JUNE 2008 CIE ABOUT KINEMATICS PAPER 1

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #33 on: October 24, 2009, 01:12:57 pm »
which question?

Offline toobeerajpanchoo

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Re: Maths & Physics Help
« Reply #34 on: October 24, 2009, 01:29:31 pm »
NO 13
13 The diagram is the speed-time graph of the first 20 seconds of a motorcyclist’s journey.
Speed
(a) Calculate the motorcyclist’s retardation during the final 8 seconds.
(b) Calculate the distance travelled in the 20 seconds.

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #35 on: October 24, 2009, 02:49:12 pm »
Will answer when i get home

Offline Ghost Of Highbury

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Re: Maths & Physics Help
« Reply #36 on: October 24, 2009, 03:10:49 pm »
NO 13
13 The diagram is the speed-time graph of the first 20 seconds of a motorcyclist’s journey.
Speed
(a) Calculate the motorcyclist’s retardation during the final 8 seconds.
(b) Calculate the distance travelled in the 20 seconds.


use the formula

v = u+at

s=ut + 0.5at2
divine intervention!

Offline toobeerajpanchoo

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Re: Maths & Physics Help
« Reply #37 on: October 24, 2009, 03:27:50 pm »
ALRIGHT  :)

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #38 on: October 24, 2009, 04:59:51 pm »
a)The final 8 seconds is a triangle base 8 height 30
area= 0.5bh=0.5*8*30=120m
b) cut up the first 12s into a triangle base 8 and height 15 so area =0.5*8*15=60
and trpezium a=15 b=30 h=4
0.5(a+b)h =0.5*(15+30)4=90
total area =60+90+120=270m

Offline sasukeuchiha

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Re: Maths & Physics Help
« Reply #39 on: May 25, 2010, 04:29:22 pm »
please give me the answer of o levels physics October/November 2008 mcq paper 1 question no. 23
please give an explanation too
http://www.freeexampapers.com/FreeExamPapers.com_.php?__lo=TyBMZXZlbC9QaHlzaWNzL0NJRS8yMDA4IE5vdi81MDU0X3cwOF9xcF8xLnBkZg==

Offline DrEvil

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Re: Maths & Physics Help
« Reply #40 on: May 25, 2010, 06:59:17 pm »
please give me the answer of o levels physics October/November 2008 mcq paper 1 question no. 23
please give an explanation too
http://www.freeexampapers.com/FreeExamPapers.com_.php?__lo=TyBMZXZlbC9QaHlzaWNzL0NJRS8yMDA4IE5vdi81MDU0X3cwOF9xcF8xLnBkZg==

The answer is C. Extend the rays beyond the mirror that are entering the eye and you'll get the explanation.


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Offline sasukeuchiha

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Re: Maths & Physics Help
« Reply #41 on: May 25, 2010, 09:20:07 pm »
many thanks :)..that was a concept left to be cleared

Offline DrEvil

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Re: Maths & Physics Help
« Reply #42 on: May 25, 2010, 09:33:17 pm »
many thanks :)..that was a concept left to be cleared

my pleasure.. 8)


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