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AS Maths P6 (Stats) predictions

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djshaheer:

--- Quote from: mac on May 24, 2009, 01:43:12 pm ---hey google....can u please show us how u would solve the attached ques, ???
 i can do the parts by the multiplication of lots of probability but that doesn't work most of times!

I consider permutation and combination as my weakest areas of statistics!!
i'm ok with probability now!! Please share the tricks to do such questions!!

I wish i had a teacher like urs.....i learnt stats 1 of the CIE book....which does get confusing at times!!

I have done all the questions (incl. misc) from that book properly...most questions are easier in pastpapers than book.  But then i have hard time solving the ones from paper...i can't get the hang of P n C questions after doing the other chapters!!!




--- End quote ---




Answer of ur pic's question:

i) P ( all three diff colors) = [3C1 x 4C1 x 5C1]÷ 12C3 = 3/11

ii) P ( exactly two peppers green) = [4C2 x 8C1] ÷ 12C3 = 12/55

iii) P ( no pepper green) = [4C0 x 8C3] ÷ 12C3 = 14/55
    p ( exactly one pepper green) = [4C1 x 8C2] ÷ 12C3 = 28/55
    P ( exactly 2 peppers green) = [4C2 x 8 C1] ÷ 12C3 = 12/55
    P ( exactly 3 peppers green) = [4C3 x 8C0] ÷ 12C3 = 1/55
    now arrange these values in a probability distribution table..  :d

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