hey google....can u please show us how u would solve the attached ques,
i can do the parts by the multiplication of lots of probability but that doesn't work most of times!
I consider permutation and combination as my weakest areas of statistics!!
i'm ok with probability now!! Please share the tricks to do such questions!!
I wish i had a teacher like urs.....i learnt stats 1 of the CIE book....which does get confusing at times!!
I have done all the questions (incl. misc) from that book properly...most questions are easier in pastpapers than book. But then i have hard time solving the ones from paper...i can't get the hang of P n C questions after doing the other chapters!!!
Answer of ur pic's question:
i) P ( all three diff colors) = [3C1 x 4C1 x 5C1]÷ 12C3 = 3/11
ii) P ( exactly two peppers green) = [4C2 x 8C1] ÷ 12C3 = 12/55
iii) P ( no pepper green) = [4C0 x 8C3] ÷ 12C3 = 14/55
p ( exactly one pepper green) = [4C1 x 8C2] ÷ 12C3 = 28/55
P ( exactly 2 peppers green) = [4C2 x 8 C1] ÷ 12C3 = 12/55
P ( exactly 3 peppers green) = [4C3 x 8C0] ÷ 12C3 = 1/55
now arrange these values in a probability distribution table.. :d