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avrila:
Plane pi has equation r.(2i +j + 2k)= 36
Point B and C has position vectors (i +3 +2k) and (3i +2j + k) respectively.

>Find the position vector of the point where the line OB meets pi and find the perpendicular distance from B to pi.

astarmathsandphysics:

--- Quote from: avrila on March 02, 2009, 02:43:57 am ---Plane pi has equation r.(2i +j + 2k)= 36
Point B and C has position vectors (i +3 +2k) and (3i +2j + k) respectively.

>Find the position vector of the point where the line OB meets pi and find the perpendicular distance from B to pi.

--- End quote ---
so subsitute into pi

We have so and t=4 and the line meets pi at. The distance is

avrila:
Ok.I got it until (4,12,8). And this is the coordinates where OB meets the plane. In other words, it is the point of intersection between the line and the plane.

But to find the distance from B to pi, why we just use the same coordinate? B has it owns coordinate right?...
Can you please explain.

astarmathsandphysics:
I corrected my post

avrila:
Ok.. I got the answer but it is slightly different.
For the distance, instead of 3,6,9 I got 6,3,6. After substitute this in the distance formula, I got 9 as the answer.

Hope I am in the right track.

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