Qualification > Math

ON 08 P4 HELP MATH!!

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theigstudent:

--- Quote from: angell on May 17, 2009, 09:40:30 pm ---Q4c
5e
 and complete Q 9 PLEASE:(

--- End quote ---
so did u get Q8 a
could u plz explain it to me

al noor:

--- Quote from: angell on May 17, 2009, 09:40:30 pm ---Q4c
5e
 and complete Q 9 PLEASE:(

--- End quote ---

Ummm sorry for Q4c i am nt suree sorry

But for Q5e...is : first draw a right angle triangle from and it ends in C
Sin 60.2=OPP/HYP
sin 60.2=OPP/85 = 73.76km


Q9 is :
a)        P =42-(12+17+8)  =5
           Q= (40-(20+8)=12
           R= 1

b) i) 17
    ii)12

c) i) 26
    ii)57

d)   i) 8/100= 2/25
      ii) 45/100=9/20

e) 37/74 * 36/73 and then u can find the answer

Hope i helped u ..and gud luck ;)

sanity_master:
Q4 C

u have to add the 2 pentagons = 536 X 2 =1070

drop a line from ) to the center of AB

then get AB by >>  sin 36 = (AB÷2)
                                            15
= 17.63

the total = (17.63X 5)+ 1070 = 5477.5 cm2

if u dont understand anything from the solution tell me

al noor:

--- Quote from: theigstudent on May 17, 2009, 09:49:03 pm ---
--- Quote from: angell on May 17, 2009, 09:40:30 pm ---Q4c
5e
 and complete Q 9 PLEASE:(

--- End quote ---
so did u get Q8 a
could u plz explain it to me

--- End quote ---

x=78(bcoz alternate angle)
y=180-36=144(bcoz opposite angle of cyclic quadratic)
z=180-78=102(bcoz opposite angle of cyclic quadratic)
 oki??

theigstudent:
thanks a lot guys
the explanations were superb  :)
Thanks once again

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