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ON 08 P4 HELP MATH!!

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astarmathsandphysics:
                1 + 2 + 3 + 4 + 5 + .................................. + n = n(n +1)
10
                                                                             2
   (a) (i) Show that this formula is true for the sum of the first 8 natural numbers.               [2]
       (ii) Find the sum of the first 400 natural numbers.                                          [1]
   (b) (i) Show that 2 + 4 + 6 + 8 + ..................... + 2n = n(n + 1).                                     [1]
       (ii) Find the sum of the first 200 even numbers.                                             [1]
      (iii) Find the sum of the first 200 odd numbers.                                              [1]
   (c) (i) Use the formula at the beginning of the question to find the sum of the first 2n natural
            numbers.                                                                                [1]
       (ii) Find a formula, in its simplest form, for
                1 + 3 + 5 + 7 + 9 + ........................ + (2n – 1).
                                                                                                    [2]
            Show your working.
ai)1+2+3+4+5+6+7+8=6=8/2(8+1)
ii)400(400+1)/2=80200
bi)AMS=2* the sum of the first 200 odd numbers=2*200(201)/2=40200
ii)ANS = sum of first 400 numbers- sum of first200 even numbers=80200-40200=40000
ci)2n(2n+1)/2=2n^2+n
ii)ANS=sum of firast wn numbers - sum of first 2n even numbers=2n^2+n- 2* sum of first n numbers=2n^2+n-2n(n+1)/2=n^2

theigstudent:
wow astar such a long post

angell:
im failing tmorrw:'(

sanity_master:
yet i couldnt get it but Thanks.....lets just hope a Q like that is not in the exam tom.  :-\

sanity_master:
i g2g ppl.......Talk to you later

and gd luck tomorrow.....we rabena yostor!!  :(

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