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Math help !

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joel:
It says 42 students like swimming so
42=12+8+17+p
So p=5
40 students like only one sport so
40=q+20+8
So q=12
There are total 100 so add all the no the subtract from 100
you will get 1
r=1

Ghost Of Highbury:
ohh.tks a lot

susman:
and yeah what about the c and e part?
need help...
thanks in advance

care:
c)i) B' contains everything that is not in the B set. So, n(B')=8+p+q+r=26
c)ii) B?F contains 20, 25, 12, 17, p, q.
S' contains 20, 25, q, r.
(B?F)?S? contains elements that are contained in both - B?F and S'.
So, n((B?F)?S?)=20+25+q=57

Ghost Of Highbury:
i onle got c i and e

c)i) n(B') means you don't take the whole of set B into consideration...therefore u r left with p q 8 and r..add them up
= 26

e)the total no. of people who like basketball are 74...12 of them also like swimming and 25 of them also like futball...so 25+12=37
the probability 4 the 1st student is 37/74
the probability for the 2nd is 36/73
multiply them
and u get 18/73

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