@sweetsh - thanx a lot
@angel - okk...so lets try the next sum
U onto Q
take any 2 co-ordinates of triangle U i.e = (-6,2) and (0,2)
arrange them vertically o form a 2 by 2 matrix
(-6 0)
(2 2)
now let say the unknown matrix of transformation is
(a b)
(c d)
so it implies that when you multiply the co-ordinates of U with the matrix of transformation, you get the co-ordinates of the image i.e triangle Q...(look at the corresponding co-ordinates of U in Q)
you can see that the point (-6,2) is mapped onto (-6,4) and (0,2) to (0,4)
soo the equation is
(-6 0) * (a b) = (-6 0)
(2 2) (c d) (4 4)
if you take (-6 0)
(2 2) to other side then it becomes the inverse...
so you multiply
(-6 0) (-6 0)
(4 4) with the inverse of (2 2)
therefore u get the answer (1 0)
(0 2)
