Qualification > Math

TRansformations

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angell:
im still confused:(

sweetsh:
Your explanation is good!

Priceless:
hmmm shan2391 c u can du it da way zara or eddie_adi619 told or in our skul dey hv thot us da base vectors which r matrixes n represent da transformations. da only bad part is dat u hv 2 lern dem. du u want dem?

reishamix:
base vectors are life savers!!
and they dnt tke long to lern
5 minutes maximum...
gd fr my level ..
which isnt too high .. =P

Ghost Of Highbury:
@sweetsh - thanx a lot   :)
@angel - okk...so lets try the next sum

U onto Q

take any 2 co-ordinates of triangle U i.e = (-6,2) and (0,2)
arrange them vertically o form a 2 by 2 matrix

(-6  0)
(2   2)

now let say the unknown matrix of transformation is
(a  b)
(c  d)

so it implies that when you multiply the co-ordinates of U with the matrix of transformation, you get the co-ordinates of the image i.e triangle Q...(look at the corresponding co-ordinates of U in Q)
you can see that the point (-6,2) is mapped onto (-6,4) and (0,2) to (0,4)
soo the equation is

(-6  0)  *   (a  b)  = (-6  0)
(2   2)       (c  d)     (4   4)

if you take (-6  0)
                (2   2) to other side then it becomes the inverse...

so you multiply

(-6  0)                            (-6  0)
(4   4) with the inverse of  (2   2)

therefore u get the answer (1  0)
                                     (0  2)

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