Qualification > Sciences
CHEM AND BIO HELP AND TIPS HERE
holtadit:
An aqueous solution contains barium iodide.
It is possible to obtain a solution that contains Ba2+(aq) but no I–(aq) by adding ……1…… until no
more ……2…… precipitate forms.
Which words correctly complete gaps 1 and 2?
1 2
A) aqueous lead(II) nitrate white
B) aqueous lead(II) nitrate yellow
C) dilute sulphuric acid white
D) dilute sulphuric acid yellow
FROM WINTER 2008 Paper 1
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I don't understand how the answer could be B. Because if BaI2 reacts with Lead Nitrate u get Lead Iodide (hence the presence of I ions) and u get Barium Nitrate.
Actually in both reactions you would get I ions and Barium ions.
HELP !
nid404:
They want only Ba2+ ions in the solution....which means they want iodide to ppt off....
so to do that, you add lead nitrate...lead iodide precipitates off and the solution contains BaNO3..
Gettin it?
holtadit:
I would just like to take this moment to say...
I LOVE CHEMISTRY !
DEGO:
--- Quote from: Ari Ben Canaan on April 08, 2010, 01:25:08 pm ---Okay for gases use the following:
moles of gas = volume of gas/24000 NOTE: use 24000 when volume in cm^3 and use 24 instead when volume is in 24 dm^3
For liquids use::
moles of liquid= (volume of liquid in cm^3 * concentration in mol/dm^3) / 1000
For solid use:
moles = mass in grams/mass number of element NOTE: if its a solid compound then add up the mass nos. of each element
--- End quote ---
Thank You ur the best
DEGO:
--- Quote from: Ari Ben Canaan on April 09, 2010, 07:41:01 am ---An aqueous solution contains barium iodide.
It is possible to obtain a solution that contains Ba2+(aq) but no I–(aq) by adding ……1…… until no
more ……2…… precipitate forms.
Which words correctly complete gaps 1 and 2?
1 2
A) aqueous lead(II) nitrate white
B) aqueous lead(II) nitrate yellow
C) dilute sulphuric acid white
D) dilute sulphuric acid yellow
FROM WINTER 2008 Paper 1
------------------------------------------------------------------------------------------------------------------------------------
I don't understand how the answer could be B. Because if BaI2 reacts with Lead Nitrate u get Lead Iodide (hence the presence of I ions) and u get Barium Nitrate.
Actually in both reactions you would get I ions and Barium ions.
HELP !
--- End quote ---
its B because its test for anion and cation he is testing for iodine tht form yellow ppt whn (acidified leadnitrate) is added got it?XD
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