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CHEM AND BIO HELP AND TIPS HERE

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Vin:

--- Quote from: Dizzy on June 06, 2010, 09:20:41 pm ---Hey Ya could someone pls do this question its really wierd cant figure it out at all


--- End quote ---

"the vol. of phosphate soln used in cm3 is half the height of the ppt in mm
also at 8cm3 all the soln is used up. tht is because adding more does not increase the height of the ppt meaning there was no further reaction on adding more.
also the formula is T3(PO4)2-----because

u take it as 12cm3 of T nitrate react with 8cm3 of sodium phosphate (thts wen all the reactants r used up)
so.....12:8...simplify it
12:8
6:4
3:2
and therefore u get T3(PO4)2"

courtesy : mohit123

$H00t!N& $t@r:

--- Quote from: ~VIN1094~ on June 06, 2010, 09:40:43 pm ---OK look at the graph, mass of the plate is constant after some time. What does it mean? No more Zn is reacting, right? So the reaction is finished. Therefore Zn is excess as it is still left after the reaction is over. Got it?

--- End quote ---
oh i see... Thanks  :)

The InViSiBlE GIrl (Eva):
ok gotcha thanks!!

--- Quote from: ~VIN1094~ on June 06, 2010, 09:41:59 pm ---
"the vol. of phosphate soln used in cm3 is half the height of the ppt in mm
also at 8cm3 all the soln is used up. tht is because adding more does not increase the height of the ppt meaning there was no further reaction on adding more.
also the formula is T3(PO4)2-----because

u take it as 12cm3 of T nitrate react with 8cm3 of sodium phosphate (thts wen all the reactants r used up)
so.....12:8...simplify it
12:8
6:4
3:2
and therefore u get T3(PO4)2"

courtesy : mohit123


--- End quote ---

7ooD:
i have urgent question in 2004 may june q 4 b iii i dnt get it at all and same paper 7 b (ii) in ms they rounded the 0.125 to 0.1  suppose it waz cuz they gave masses to 1 decimal why they didnt do the same in c (i) and (ii)

nid404:
Attach the paper please

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