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CHEM AND BIO HELP AND TIPS HERE

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8T:

--- Quote from: Kimo Jesus on June 06, 2010, 08:01:26 pm ---first you find the moles of fe2o3 which is  .08


and thn the ration of moles of gases = 2: 1 therfore .04

and there are two gases

so . 04 + .04

--- End quote ---
Fe2o3 is 0.04 not 0.08 .. soo?

WARRIOR:

--- Quote from: 8T on June 06, 2010, 08:03:56 pm ---Fe2o3 is 0.04 not 0.08 .. soo?

--- End quote ---
sorry i meant fe2so4

12.16 /152

Vin:
c)

1. 12.16/152 g= 0.08 moles

2. Molar ratio
= 2 : 1
= 0.08 : x
so x= 0.04

3. 56+56+16+16+16 = 160g

4.  moles = mass/mass of 1 mole

mass = 0.04 * 160
=6.4g

5. two gases so 0.04 + 0.04 = 0.08mol

6. vol of gas = 0.08 * 24
= 1.92

$H00t!N& $t@r:
ok i have a silly question...  :-[      s05 q2c (i)  
how do u knw which one is in excess?

The InViSiBlE GIrl (Eva):

--- Quote from: CatAly$t on June 05, 2010, 08:13:46 pm ---somebody pls explain to me this...

--- End quote ---
Hey Ya could someone pls do this question its really wierd cant figure it out at all

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