Qualification > Sciences

CHEM AND BIO HELP AND TIPS HERE

<< < (518/680) > >>

sarasa:

--- Quote from: thenewkid™ on June 05, 2010, 01:09:13 pm ---hope this is wht u need

--- End quote ---
Thanks

sarasa:

--- Quote from: ahmediiii on June 05, 2010, 01:18:19 pm ---or maybe this.... idk if its correct

--- End quote ---
Thanks

rameeziiii:

--- Quote from: ahmediiii on June 05, 2010, 01:27:46 pm ---looking it up

--- End quote ---
ok...umm...well... OK!...
79.1g of CaSO4 is 79.1/136 moles of CaSO4 (i.e. 0.58 moles)
20.9g of H2O is 20.9/18 moles water (ie. 1.16 moles)
now divide by the simplest mole ratio (0.58) to obtain X

$H00t!N& $t@r:

--- Quote from: Jaw@!r!a on June 05, 2010, 01:21:24 pm ---m/j 2005
chem ppr 3
q4 d   
how do u noe x=2
Thanks

--- End quote ---

mol=mass/MM    so for CaSO4 : mol=79.1/136 = 0.58mol    and for H2O: mol=20.9/18= 1.16mol
To find x you have to find the mole ratio
so divide each of them with the smallest one
therefore in this case 0.58mol is smaller than 1.16 so    0.58/0.58=1  and x=   1.16/0.58=2   therefore x=2

$H00t!N& $t@r:

--- Quote from: ahmediiii on June 05, 2010, 01:34:07 pm ---ok...umm...well... OK!...
79.1g of CaSO4 is 79.1/136 moles of CaSO4 (i.e. 0.58 moles)
20.9g of H2O is 20.9/18 moles water (ie. 1.16 moles)
now divide by the simplest mole ratio (0.58) to obtain X

--- End quote ---

oops didnt see you already replied  :P

Navigation

[0] Message Index

[#] Next page

[*] Previous page