sorry for taking so long...some important calls
Anyway
Na3PO4+ nTx(NO3)y----> NaNO3+ Tnx(PO4)z
all the variables are unknown at present
U know the reaction will give sodium nitrate which has the formula NaNO3[/sub]....now u also know the volume of the product is 8cm3
the volume of sodium phosphate is 2cm3...
The mole ratio of sodium phosphate and Tnitrate is 2:3, when u try to balance for NaNO3...and u get (NO3)2. The product side has 6NaNO3
This gives us the charge on T as +2...since (NO3)2-...u know PO4 will be twice and thus T will be thrice cuz of the charges
Little weird to understand...ill put down the balanced equation, which is likely to make it easy for u to figure it out
2 Na3PO4+ 3 T(NO3)2---->6NaNO3+ T3(PO4)2
I'll try explaining again...i tried my best to explain tho...