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CHEM AND BIO HELP AND TIPS HERE

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@d!_†oX!©:
Even i think it should be C
thanks aadi

nid404:
yes ofc it's C

@d!_†oX!©:
ok people..here i am again...

Tungsten metal, W, is manufactured by reducing tungsten(III)oxide, WO3, whit carbon.

WO3 + 3C -----> 3CO + W

Calculate the mass of carbon needed to reduce 116g of tungsten(III)oxide.

-------------------------------------------------------------------------------------------------------------------------------
Now, I know how to do it.
We first take out the number of moles of WO3
which comes out to be 116/232 = 0.5 moles
Then, as the ratio is 1:3
Thus, the number of moles of C = 0.5*3 = 1.5 moles
Thus, the mass of carbon = 1.5*12 = 18g

Now my question,
if the ratio according to the equation is 1:3 for WO3:C
The how is it possible that for 116g of WO3 only 18g of C is required?

So, i thought maybe i have done it wrong although this is the correct method itself, but i still tried
Having the mass of WO3 as 116g and the ratio being 1:3
thus, the mass of C be 3*116 = 348g

But, the second method is wrong, isn't it?
then how are we getting 18g as the mass of Carbon required??

Please help guys!!!

Ghost Of Highbury:
wats the answer?

@d!_†oX!©:
That's the problem dude...i don't have the answer...... :-[

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