Qualification > Math
[Math: Vectors] Clear my doubts please
Dasith:
--- Quote from: Becca on September 04, 2011, 02:17:02 pm ---Dear Ricky, you actually did everything correctly... :) However, when you came to 'OX=PX-PO', I think that you accidentally substituted 'q' into 'PO' instead of 'p'. If you do this, you will get the answer...
To Darsith, I'm thinking that maybe you did something wrong in your calculations along the way, and forgot about the denominator of 3. I hope that I helped. :)
--- End quote ---
& yeap i think i 4got da denominator , its P +( (-p+q)/3)= OX, but i dnt see anything wrong wid my calculations , can u tell me where exactly i went wrong in da calculations ?
Becca:
Hi Dasith, sorry for the late reply... >< I was a little tied up with my exams...
I shall include my working for the second part of the question here, the one on finding OX:
OX=OP+PX
=p + 1/3(-p+q)
=p - 1/3p+ 1/3q
=2/3p + 1/3q
When I saw that Ricky said that the answer is '1/3(2q+p)' , I was stumped as it was different from the answer I got above. However, I checked the answer scheme, which said that my answer is correct. It's actually '1/3(2p+q)... Do you see any difference between your working and mine? :) Do let me know if you have any further difficulties...
Dasith:
--- Quote from: Becca on September 18, 2011, 05:59:00 am ---Hi Dasith, sorry for the late reply... >< I was a little tied up with my exams...
I shall include my working for the second part of the question here, the one on finding OX:
OX=OP+PX
=p + 1/3(-p+q)
=p - 1/3p+ 1/3q
=2/3p + 1/3q
When I saw that Ricky said that the answer is '1/3(2q+p)' , I was stumped as it was different from the answer I got above. However, I checked the answer scheme, which said that my answer is correct. It's actually '1/3(2p+q)... Do you see any difference between your working and mine? :) Do let me know if you have any further difficulties...
--- End quote ---
isnt 2/3P + 1/3q the same as " P +( (-p+q)/3)"
simplify it & u get da same O.o !
Becca:
Hmm, are you trying to say that my method is quite long-winded?? :-[ Heheh, I get that a lot... I guess that the A level course that I am currently taking is getting to my head! XD 8)
Anyway, you were right about the answer to b(i) posted by Ricky being wrong... I missed that earlier. And yes, your method also gets the same answer of 2/3p+1/3q... but isn't it almost the same as my method? Hmm... I mean that isn't 'p + 1/3(-p+q)' the same as p +(-p+q)/3 :o
Other than the part where you forgot the denominator of 3 :) I think that you got the rest of the working correct... It all seems fine to me, though that little mistake did prevent you from getting the answer.
Ermm, do you understand what I'm trying to say? :-\
Dasith:
--- Quote from: Becca on September 21, 2011, 03:27:55 pm ---Hmm, are you trying to say that my method is quite long-winded?? :-[ Heheh, I get that a lot... I guess that the A level course that I am currently taking is getting to my head! XD 8)
--- End quote ---
all wat i'm tryin 2 sat i missed da denominator 3 in my first post accidently , u r meathod is fine as well as mine, dosent make any of our ans wrong..
--- Quote from: Becca on September 21, 2011, 03:27:55 pm ---
Anyway, you were right about the answer to b(i) posted by Ricky being wrong... I missed that earlier. And yes, your method also gets the same answer of 2/3p+1/3q... but isn't it almost the same as my method? Hmm... I mean that isn't 'p + 1/3(-p+q)' the same as p +(-p+q)/3 :o
--- End quote ---
this is what i said in my previous post , when u simplify my ans u get yours :)
--- Quote from: Becca on September 21, 2011, 03:27:55 pm ---
Ermm, do you understand what I'm trying to say? :-\
--- End quote ---
yeap , i think i misread some o u r posts O.o
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