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STATISTICS DOUBT!!! PLZ REPLY ASAP!!!

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I Jimmy I:
Ok guys, I have another doubt. :(

Question 5(iii) and (iv) of M/J 2010 ----2nd variant-----

Given, P(Q)= 1/24
P(R)=1/9

Question is,
(iii)Are events Q and R exclusive? Justify your answer.
(iv)Are events Q and R independent? Justify your answer.

If my memory serves me well then exclusive is (A.B)=0 and independent is (A.B) NOT= 0
Marking Scheme says that Q and R are exclusive but ( 1/24*1/9) isnt 0 so HOW...?

EMO123:

--- Quote from: I Jimmy I on May 25, 2011, 10:00:55 am ---Ok guys, I have another doubt. :(

Question 5(iii) and (iv) of M/J 2010 ----2nd variant-----

Given, P(Q)= 1/24
P(R)=1/9

Question is,
(iii)Are events Q and R exclusive? Justify your answer.
(iv)Are events Q and R independent? Justify your answer.

If my memory serves me well then exclusive is (A.B)=0 and independent is (A.B) NOT= 0
Marking Scheme says that Q and R are exclusive but ( 1/24*1/9) isnt 0 so HOW...?

--- End quote ---
5(iii)
if P(R and Q)=0
then it is Exclusive

EMO123:

--- Quote from: I Jimmy I on May 25, 2011, 10:00:55 am ---Ok guys, I have another doubt. :(

Question 5(iii) and (iv) of M/J 2010 ----2nd variant-----

Given, P(Q)= 1/24
P(R)=1/9

Question is,
(iii)Are events Q and R exclusive? Justify your answer.
(iv)Are events Q and R independent? Justify your answer.

If my memory serves me well then exclusive is (A.B)=0 and independent is (A.B) NOT= 0
Marking Scheme says that Q and R are exclusive but ( 1/24*1/9) isnt 0 so HOW...?

--- End quote ---
5 (iv)
if P(R and Q)=P(R) * P(Q)
then it is Independent
But if it is not equal to it then it is not independent

Ghost Of Highbury:

--- Quote from: I Jimmy I on May 25, 2011, 09:56:40 am ---Continuity Correction. Its used when Binomial distributions are converted to Normal distributions when np and nq>5
So u either add or subtract 0.5 to the given P(X>n)

P.S "n" in the P(X>n) is any constant :)

--- End quote ---

Ah ok, thanks

I Jimmy I:

--- Quote from: EMO123 on May 25, 2011, 10:13:08 am ---5(iii)
if P(R and Q)=0
then it is Exclusive


--- End quote ---
thats what I thought but P(R)*P(Q) is not 0 even tho the Marking scheme said the opposite...

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