Qualification > Math
STATISTICS DOUBT!!! PLZ REPLY ASAP!!!
I Jimmy I:
Ok guys, I have another doubt. :(
Question 5(iii) and (iv) of M/J 2010 ----2nd variant-----
Given, P(Q)= 1/24
P(R)=1/9
Question is,
(iii)Are events Q and R exclusive? Justify your answer.
(iv)Are events Q and R independent? Justify your answer.
If my memory serves me well then exclusive is (A.B)=0 and independent is (A.B) NOT= 0
Marking Scheme says that Q and R are exclusive but ( 1/24*1/9) isnt 0 so HOW...?
EMO123:
--- Quote from: I Jimmy I on May 25, 2011, 10:00:55 am ---Ok guys, I have another doubt. :(
Question 5(iii) and (iv) of M/J 2010 ----2nd variant-----
Given, P(Q)= 1/24
P(R)=1/9
Question is,
(iii)Are events Q and R exclusive? Justify your answer.
(iv)Are events Q and R independent? Justify your answer.
If my memory serves me well then exclusive is (A.B)=0 and independent is (A.B) NOT= 0
Marking Scheme says that Q and R are exclusive but ( 1/24*1/9) isnt 0 so HOW...?
--- End quote ---
5(iii)
if P(R and Q)=0
then it is Exclusive
EMO123:
--- Quote from: I Jimmy I on May 25, 2011, 10:00:55 am ---Ok guys, I have another doubt. :(
Question 5(iii) and (iv) of M/J 2010 ----2nd variant-----
Given, P(Q)= 1/24
P(R)=1/9
Question is,
(iii)Are events Q and R exclusive? Justify your answer.
(iv)Are events Q and R independent? Justify your answer.
If my memory serves me well then exclusive is (A.B)=0 and independent is (A.B) NOT= 0
Marking Scheme says that Q and R are exclusive but ( 1/24*1/9) isnt 0 so HOW...?
--- End quote ---
5 (iv)
if P(R and Q)=P(R) * P(Q)
then it is Independent
But if it is not equal to it then it is not independent
Ghost Of Highbury:
--- Quote from: I Jimmy I on May 25, 2011, 09:56:40 am ---Continuity Correction. Its used when Binomial distributions are converted to Normal distributions when np and nq>5
So u either add or subtract 0.5 to the given P(X>n)
P.S "n" in the P(X>n) is any constant :)
--- End quote ---
Ah ok, thanks
I Jimmy I:
--- Quote from: EMO123 on May 25, 2011, 10:13:08 am ---5(iii)
if P(R and Q)=0
then it is Exclusive
--- End quote ---
thats what I thought but P(R)*P(Q) is not 0 even tho the Marking scheme said the opposite...
Navigation
[0] Message Index
[#] Next page
[*] Previous page
Go to full version