STATISTICS DOUBT!!! PLZ REPLY ASAP!!!

[SkyPilotage]

Tyvm

YAMW

[Ghost Of Highbury]

To my knowledge, using the normal distribution to calculate the probability of a random variable X > q (where q is an integer) is the same as
the probability of x >=q. So by mistake, if u make an error in the sign, your final answer won't change. However, you may lose marks for
not using the correct sign if the question clearly stated the conditions.

[I Jimmy I]

P(X>10) = P(V>10.5) when using C.C
P(X>=10) = P(V>=9.5) when using C.C

So it does matter a LOT

[Ghost Of Highbury]

P(X>10) = P(V>10.5) when using C.C
P(X>=10) = P(V>=9.5) when using C.C

So it does matter a LOT

Yes, for normal distribution model, it does matter agreed.

What's C.C?

[EMO123]

Tyvm

what is this Tyvm?

[I Jimmy I]

what is this Tyvm?

Thank You Very Much

[EMO123]

Thank You Very Much

ohh tyvm

[I Jimmy I]

ohh tyvm

Lol your welcome

[SkyPilotage]

Yes, for normal distribution model, it does matter agreed.

What's C.C?

Continuity Correction When aproximating a B.D as a Normal D....

[I Jimmy I]

Yes, for normal distribution model, it does matter agreed.

What's C.C?

Continuity Correction. Its used when Binomial distributions are converted to Normal distributions when np and nq>5
So u either add or subtract 0.5 to the given P(X>n)

P.S "n" in the P(X>n) is any constant

[I Jimmy I]

Ok guys, I have another doubt.

Question 5(iii) and (iv) of M/J 2010 ----2nd variant-----

Given, P(Q)= 1/24
P(R)=1/9

Question is,
(iii)Are events Q and R exclusive? Justify your answer.
(iv)Are events Q and R independent? Justify your answer.

If my memory serves me well then exclusive is (A.B)=0 and independent is (A.B) NOT= 0
Marking Scheme says that Q and R are exclusive but ( 1/24*1/9) isnt 0 so HOW...?

[EMO123]

Ok guys, I have another doubt.

Question 5(iii) and (iv) of M/J 2010 ----2nd variant-----

Given, P(Q)= 1/24
P(R)=1/9

Question is,
(iii)Are events Q and R exclusive? Justify your answer.
(iv)Are events Q and R independent? Justify your answer.

If my memory serves me well then exclusive is (A.B)=0 and independent is (A.B) NOT= 0
Marking Scheme says that Q and R are exclusive but ( 1/24*1/9) isnt 0 so HOW...?

5(iii)
if P(R and Q)=0
then it is Exclusive

[EMO123]

Ok guys, I have another doubt.

Question 5(iii) and (iv) of M/J 2010 ----2nd variant-----

Given, P(Q)= 1/24
P(R)=1/9

Question is,
(iii)Are events Q and R exclusive? Justify your answer.
(iv)Are events Q and R independent? Justify your answer.

If my memory serves me well then exclusive is (A.B)=0 and independent is (A.B) NOT= 0
Marking Scheme says that Q and R are exclusive but ( 1/24*1/9) isnt 0 so HOW...?

5 (iv)
if P(R and Q)=P(R) * P(Q)
then it is Independent
But if it is not equal to it then it is not independent

[Ghost Of Highbury]

Continuity Correction. Its used when Binomial distributions are converted to Normal distributions when np and nq>5
So u either add or subtract 0.5 to the given P(X>n)

P.S "n" in the P(X>n) is any constant

Ah ok, thanks

[I Jimmy I]

5(iii)
if P(R and Q)=0
then it is Exclusive

thats what I thought but P(R)*P(Q) is not 0 even tho the Marking scheme said the opposite...