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statistics CIE AS level doubts!!

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Ghost Of Highbury:
5. 6i) 1 2 3 4 5 - 10 outcomes - 123 345 124 245 125 235 134 234 135 145
     odd number sum - 4/10 =  0.4
6ii)  largest number 4 - 124 134 234 = 3/10 = 0.3

6iii) L can take values 3 4 5

     use the same method as done previously (in ii), list from the possible outcomes and calculate the probability
 
6iv) E(X) = sum (l*p)
      Variance = Sum(li^2pi) -( (E(x))^2

6. 6iii) P(A|B) = P(AnB) / P(B) = 0.65*0.1 / (your answer to part ii) = 5/19

   7ii) The probability of atleast one damaged tape = 1 - P(no damaged tape)

        probability of no damaged tape = 1-0.2 = 0.8

         1 - (0.8 )^n >= 0.85

        n = 9

Tohru Kyo Sohma:

--- Quote from: Ghost Of Highbury~ on May 20, 2011, 08:58:18 am ---
6. 6iii) P(A|B) = P(AnB) / P(B) = 0.65*0.1 / (your answer to part ii) = 5/19

   7ii) The probability of atleast one damaged tape = 1 - P(no damaged tape)

        probability of no damaged tape = 1-0.2 = 0.8

         1 - (0.8 )^n >= 0.85

        n = 9



--- End quote ---
its 0.8^n
how can u find n......i didnt get it.....is there a method......pls do tell........and thanks for helping too

Tohru Kyo Sohma:
ok......i have a doubt...not pastpaper this time....how do we know when to give a plus or minus sign in normal distribution qns......like when they ask to find standard deviation or mean....then im never sure when "z" should be + or -
HELP ME

Tohru Kyo Sohma:
ok...there is this qns in o/n 2009 p61 qns 3 part 2
they use 0.33 instead of 0.34.............i dont get it...y??

Tohru Kyo Sohma:
ok...i have 1 more (endless doubts ;D)....oct/nov 2009 p61 qns 5

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