Qualification > Math

Pls help as soon as possible

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SauD~:

--- Quote from: The Nerdy Pro on May 14, 2011, 08:00:49 pm ---i got everything exce[t x 5? why x 5?

--- End quote ---
we have different class widths of diff sets of values :)
So the 11.5 is done by multiplying it with 5, to make it a common.. .
got it?
to make something in common in class width they multiplied it with 5
otherwise it should have been 115/2 = 57.5 cm

to make common in class width :)

Most UniQue™:

--- Quote from: $~SauD~$ on May 14, 2011, 08:14:39 pm ---we have different class widths of diff sets of values :)
So the 11.5 is done by multiplying it with 5, to make it a common.. .
got it?
to make something in common in class width they multiplied it with 5
otherwise it should have been 115/2 = 57.5 cm

to make common in class width :)


--- End quote ---

No :( u mean in order to make it 11.5 u multiply it by 5?

SauD~:

--- Quote from: The Nerdy Pro on May 14, 2011, 09:47:50 pm ---No :( u mean in order to make it 11.5 u multiply it by 5?

--- End quote ---
DUde.
To find the length for 115 frequency thing,

Length is found by frequency density formula... so f.d. = frquency/class width
                                                                                  115/2 = 57.5  but they said it is 11.5
                                                        if we do like this   115/2 x 5  that will give 11.5
so they multiplied it with 5   

Most UniQue™:

--- Quote from: $~SauD~$ on May 15, 2011, 10:58:06 am ---DUde.
To find the length for 115 frequency thing,

Length is found by frequency density formula... so f.d. = frquency/class width
                                                                                  115/2 = 57.5  but they said it is 11.5
                                                        if we do like this   115/2 x 5  that will give 11.5
so they multiplied it with 5   


--- End quote ---

Yah I already got it Thanks

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