can sum1 please do and explain q 5 and 6 in paper 6 CIE math, in november 02...
thanks in advance
Question 6
part 1)
P(chocolate biscuit)=q=1/4
P(cream biscuit)=p=3/4
n=10
10C5(3/4)^5(1/4)^5=0.0584
2)
n=8
p=0.0584
q=0.9416
P(x=1)=8C1(0.0584)(0.9416)^7
=0.307
part 3) apply continuity correction
and use normal distribution
you can do this i am sure