Sorry, but I got confused here..
Bold text inside the quote was written
by me.
...
eg. A voltmeter might read: 1.25v +/-0.01v. (I guess here is a mistake, because the rest assumes it's +/-0.1v) This implies voltage between 1.24 and 1.26
Actual uncertainty therefore would be:
1mm for the rule
0.1 for the voltmeter (not 0.01?)
0.01mm for the micrometer
This can also be written as % uncertainty using the following formula:
...
Examples:
1. Finding R using a voltmeter and an ammeter if the reading on the voltmeter is 2.45v and the ammeter is 0.96A:
V=2.54 +/-0.01v
% error = 0.01/2.54*100 = 4% (not 0.3937...~0.4?)
I= 0.96A +/-A
0.01/0.96*100= 1%
combined error: 4% (0.4%)+1%= 5% (1.4% ~1%)
r=v/i
2.54/0.96 =2.56 +/- 5% (not 5%) ohms
Thanks for notes by the way!