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math questions. =S

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anusha500:
i attached a question. i cant seem to get the same answer to part D. could someone else pls try.

another question.

find h.       2h=100/h^2

so u get (2h)*(h^2)=100
how do you simplify tht?
2h^3 or 2h^5 ?

astarmathsandphysics:
2h^3=100 so h^3=50 so h=cube root of 50

Use cosine rule to find AD
AD2=8^2+7^2-2*8*7*cos80=93.55 so  AD=9.67
Then cut OAD  into 2 right angled triangles with angles 80 at centre. trig gives r=4.836/sin80=4.91

SGVaibhav:
why not sine rule

plus my answer is coming 4.90 using trigonometry and sine rule.

how?

astarmathsandphysics:
2h^3=100 so h^3=50 so h=cube root of 50

Use cosine rule to find AD
AD2=8^2+7^2-2*8*7*cos80=93.55 so  AD=9.67
Then cut OAD  into 2 right angled triangles with angles 80 at centre. trig gives r=4.836/sin80=4.91
Think their answer must be wrong. Examined everything.

SGVaibhav:
now its time to show off!!  [party time]
 8)

now i wonder how can I and Mr. Paul be wrong

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