Author Topic: c1 edexcel exams 11th january 2011  (Read 5234 times)

Offline otrivine

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c1 edexcel exams 11th january 2011
« on: January 10, 2011, 04:28:57 pm »
hi how did everyone find the exam??

Offline The Golden Girl =D

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Re: c1 edexcel exams 11th january 2011
« Reply #1 on: January 10, 2011, 04:44:35 pm »
your NOT allowed to discuss the exams until 24 hours have passed.

so kindly refrain from doing so.
Verily, in the remembrance of Allah do hearts find rest(13:28)

Please, Don't forget to Include GG in your Prayers =D

Offline Dibss

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Re: c1 edexcel exams 11th january 2011
« Reply #2 on: January 10, 2011, 04:57:58 pm »
What time will it be when 24 hours have passed?

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Re: c1 edexcel exams 11th january 2011
« Reply #3 on: January 10, 2011, 05:27:06 pm »
Since I finished MY exam at 10:00 am GMT *Monday* ,and So  It's at 10:00 am GMT *Tuesday*

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Offline saadmannan

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Re: c1 edexcel exams 11th january 2011
« Reply #4 on: January 11, 2011, 11:54:22 am »
Here is the model answer for C1 and C2

Offline otrivine

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Re: c1 edexcel exams 11th january 2011
« Reply #5 on: January 11, 2011, 01:09:23 pm »
does nyone know the grade boundaires for janaury 2011 exams

is it something like 55/75 for an A?

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Re: c1 edexcel exams 11th january 2011
« Reply #6 on: January 11, 2011, 01:29:15 pm »
+ rep saadmannan
Verily, in the remembrance of Allah do hearts find rest(13:28)

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Offline blackberry

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Re: c1 edexcel exams 11th january 2011
« Reply #7 on: January 11, 2011, 02:46:10 pm »
guys in 9c in the formula to find the equation y-4=-2/3(x-1)
when you take 3 to the other side its negative not positive since both the denominator and nominator are negative so the answer should be 2x-3y+14. Correct me if im wrong!! :)
You gotzz to cheel!!!! tuh-may-toez and un-yunz!!!
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Offline saadmannan

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Re: c1 edexcel exams 11th january 2011
« Reply #8 on: January 11, 2011, 03:51:04 pm »
guys in 9c in the formula to find the equation y-4=-2/3(x-1)
when you take 3 to the other side its negative not positive since both the denominator and nominator are negative so the answer should be 2x-3y+14. Correct me if im wrong!! :)

only the numerator has -ve sign and not the denominator when we shift 3 it will have +ve sign thus we get the equation 2x+3y-14

Offline blackberry

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Re: c1 edexcel exams 11th january 2011
« Reply #9 on: January 11, 2011, 04:12:56 pm »
only the numerator has -ve sign and not the denominator when we shift 3 it will have +ve sign thus we get the equation 2x+3y-14

how??? the whole fraction shud be negative shudnt it?? thats what my teacher told me and i was solving this other past paper and it showed that the denominator is negative in the mark scheme.......  ??? ???
You gotzz to cheel!!!! tuh-may-toez and un-yunz!!!
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elemis

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Re: c1 edexcel exams 11th january 2011
« Reply #10 on: January 11, 2011, 04:25:32 pm »
how??? the whole fraction shud be negative shudnt it?? thats what my teacher told me and i was solving this other past paper and it showed that the denominator is negative in the mark scheme.......  ??? ???

If I remember correctly the gradient was -2/3

Offline blackberry

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Re: c1 edexcel exams 11th january 2011
« Reply #11 on: January 11, 2011, 04:29:32 pm »
If I remember correctly the gradient was -2/3

dude how can the nominator and denominator be different??
You gotzz to cheel!!!! tuh-may-toez and un-yunz!!!
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Offline saadmannan

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Re: c1 edexcel exams 11th january 2011
« Reply #12 on: January 11, 2011, 04:30:12 pm »
how??? the whole fraction shud be negative shudnt it?? thats what my teacher told me and i was solving this other past paper and it showed that the denominator is negative in the mark scheme.......  ??? ???

@Ari yes u are correct the gradient was -2/3
@blackberry if both the denominator and numerator are negative the fraction would become positive -2/-3= 2/3

Offline blackberry

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Re: c1 edexcel exams 11th january 2011
« Reply #13 on: January 11, 2011, 04:31:29 pm »
noooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo i lost 2 marks!!!!!!!!!!!!!!
You gotzz to cheel!!!! tuh-may-toez and un-yunz!!!
:)

elemis

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