Qualification > Math

Differentiation Question

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Dibss:
Sorry, I haven't used the rule for months now - rusty. :S
My bad. So you probably got the answer after using the correct rule right?

Dibss:
&& you get the correct answer using the product rule

y=(1-S)(C-1)

dy/dx = (1-S)(S/C2)+(C-1)(0-C)
=S(1-S))/(1-S2) + 1/C (-C)
=S(1-S)/(1+S)(1-S)  - 1
=(S + 1 - S)/(1+S)
=1/(1+S)

Chingoo:
Thanks a lot! =D +rep

Dibss:
No problemm. (:

Tohru Kyo Sohma:
i kind of find maths AS very hard....especially differentiation.....i have a doubt here:
find the coordinates of the point on the curve y=2x^2 -x-1, where the tangent is parallel to the line; y=3x-2?

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