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[CIE] All Pure Mathematics (P1, P2 and P3) doubts here !

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White Eagle:
chan any one explain how a vector equestion is found from a cartesian equestion

I AM stuck with
Find vector equestion of cartesian equestion
x+3y=7

astarmathsandphysics:
Do you mean for lines?
http://astarmathsandphysics.com/a_level_maths_notes/C4/a_level_maths_notes_c4_changing_between_cartesian_and_vector_forms_of_equations_of_lines.html

donhassan:
hello everyone please help me out in this question please


The planes p1 and p2 have equations X+Y-Z=0 AND 2X-4Y+Z+12=0 respectively.
1.) find the numbers p,q,r such that vector (p,q,r) is parallel to both p1 and p2
2.)hence find the equation of the plane through the point (3,8,2) which is perpendicular  to both p1 and p2


answer:1.)p=1 q=1 r=2
           2.)X+y+2z=15
guys pls explain me in lucid way

thanks
donhassan

astarmathsandphysics:
1. The normals are n_1=(1,1,-1) and n_2=(2,-4,1)
find n_1 x n_2 =(-1,-1,-6)
2.-3x-3y-6z=d
Put x=3,y=8, z=2 to find d=-45 so -3x-3y-6z=-45
and dividing by -3 gives x+y+2z=15

donhassan:

--- Quote from: astarmathsandphysics on March 12, 2012, 07:36:24 pm ---1. The normals are n_1=(1,1,-1) and n_2=(2,-4,1)
find n_1 x n_2 =(-1,-1,-6)
2.-3x-3y-6z=d
Put x=3,y=8, z=2 to find d=-45 so -3x-3y-6z=-45
and dividing by -3 gives x+y+2z=15

--- End quote ---

sir i didn't understood first part :(

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