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[CIE] All Pure Mathematics (P1, P2 and P3) doubts here !

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Alpha:

--- Quote from: $H00t!N& $t@r on November 22, 2010, 05:20:45 pm ---wow am I the only one asking questions?  :-[

Anyway, I have another question!

Q) The equation of a curve is y = 3 cos 2x. The equation of a line is x + 2y = pie. On the same diagram, sketch the curve and the line for 0<= x<= pie.  

The question is from O/N 2009 paper

Thanks  ;D

--- End quote ---

I answered this question of yours already in the Add Maths thread. ;)


--- Quote from: samih.mabsout on November 22, 2010, 07:19:35 pm ---y=4x^4+4x+9
i) Find the coordinates of the stationary point on the curve and determine its nature.
ii) Find the area of the region enclosed by the curve, the x-axis and the lines x=0 and x=1

* paper 1/oct/nov/2009 question 4*

--- End quote ---

(i)

It's not 4x4, it's x4.

dy/dx= 4x3+4

At Stat. pt, gradient i.e. dy/dx= 0,

                       4x3+4 = 0
                                    x= -1

Subs. x= -1 in eqn. of curve:
    y= 1-4+9
    y=6

Therefore, coor. are (-1, 6).

d2y/dx2= 12x2

Rep. x=-1, d2y/dx2= 12, which is positive.
Therefore, it's a minimum curve.

(ii)

y=  x4 + 4x + 9

Integrate y w.r.t. x from x=0 to x=1.

,/ : Integration of      

,/y= x5/5 + 4x2/2 + 9x
    = x5/5 + 2x2 + 9x  

Area = 15/5 + 2(1)2 + 9(1) - 05/5 + 2(0)2 + 9(0)

You can use your calculator. Good luck. ;)                              

$H00t!N& $t@r:
thanks Alpha!  :)

Alpha:

--- Quote from: $H00t!N& $t@r on November 25, 2010, 05:48:43 pm ---thanks Alpha!  :)

--- End quote ---

Welcome.  :)

HUSH1994:
anyone has some notes or something that can help about vectors

elemis:

--- Quote from: HUSH1994 on November 29, 2010, 02:40:43 pm ---anyone has some notes or something that can help about vectors

--- End quote ---

Rather than just asking for 'notes', please specify a section or type of question you have issues dealing with.

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