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[CIE] All Pure Mathematics (P1, P2 and P3) doubts here !

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astarmathsandphysics:
f : x  ? 3 ? 2 tan(1 x)
should that be tan^-1 x

Arthur Bon Zavi:
(7) (i)

First keep the value of x as 0 in f(x), you will get 3. Then keep a higher value, for example f(0.5 pie), you will get 1. So as you move from 0 to pie, the value of f(x) is decreasing so the range is :

(ii)

f(2/3 pie)
= 3 - 2tan(0.5 X 2/3 pie)
= 3 - 2tan(1/3 pie)
= 3 - 2 ()
= ( - 2)

(iii)

You simply need to draw the graph. Make sure you plot the graph only for the range given in the question.

(iv)

f(x) = 3 - 2 tan(x), then let f(x) be y

y = 3 - 2tan(x)
2tan(x) = 3 - y
tan(x) =
x = tan-1
x = 2 X tan-1

y = 2 X tan-1

astarmathsandphysics:
thanks

Arthur Bon Zavi:

--- Quote from: astarmathsandphysics on October 11, 2011, 09:35:14 am ---thanks

--- End quote ---

No problem, sire.

ashwinkandel:
@Arthur Bon Zavi If you can , can you plz show me show the graph looks like?? This is the first time i have come through a question in CIE Maths exam where graph of tanx has been asked to plot... I know how to plot for y=tanx ... but this y=3-tan(x/2)  for domain 0<=x<2pi seems complicated..

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