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[CIE] All Pure Mathematics (P1, P2 and P3) doubts here !

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astarmathsandphysics:
the modulus question above - answer attacjed

cs:

--- Quote from: astarmathsandphysics on September 23, 2011, 11:06:32 am ---the modulus question above - answer attacjed

--- End quote ---

thanks! we can only use graph method for this question?

cs:

--- Quote from: S.M.A.T on September 09, 2011, 08:03:00 pm ---
dy/dx=(2xe^-x)-((x^2)(e^-x)) from part ii


let the tangent be y=mx

At point of intersection,

mx=(x^2)(e^-x)
after solving
m=0 or m=x(e^-x)

m=(dy/dx)
therefore,
x(e^-x)=(2xe^-x)-((x^2)(e^-x))
after solving,x=1

I think there is a short method which I don't now  :-\


having doubt for this question too, thanks!






--- End quote ---


having doubt for this question too, thanks!

astarmathsandphysics:
no you can also square both sides but I like the graph method cos it make the answer more obvious I think

cs:
can you show me please, i cant get the answer using squaring both sides, sorry to bother you :)

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