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[CIE] All Pure Mathematics (P1, P2 and P3) doubts here !

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elemis:
Expanding (2-x)6 up to the term containing x2 gives :

64 - 192x +240x2

Multiply this by (1+kx) giving :

64 - 192x + 240x2 +64kx -192kx2 +240kx3

Since x2 should not be present the sum of the co-efficients of the x2 terms must add up to zero.

Therefore, 240 -192k = 0

k = 1.25

$H00t!N& $t@r:
thanks alot Ari  ;D
+rep

elemis:

--- Quote from: $H00t!N& $t@r on November 16, 2010, 03:46:52 pm ---thanks alot Ari  ;D
+rep

--- End quote ---

Anytime :)

$H00t!N& $t@r:
how do you find the range of a fuction?  ??? i read the book but i dont understand it  :-\

can someone help me with m/j 05 q7 (i) and (iii)  please explain the answer in (iii) Thanks

elemis:

--- Quote from: $H00t!N& $t@r on November 17, 2010, 10:18:33 am ---how do you find the range of a fuction?  ??? i read the book but i dont understand it  :-\

can someone help me with m/j 05 q7 (i) and (iii)  please explain the answer in (iii) Thanks

--- End quote ---

Sorry, I cant do this, havent done it yet.

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