Qualification > Math

[CIE] All Pure Mathematics (P1, P2 and P3) doubts here !

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--- Quote from: SkyPilotage on May 18, 2011, 06:14:24 pm ---Just square both sides..

--- End quote ---
and to find the range
just put the values -7 and 1 on a number line

take out any value less than 1 like 0 and put it into (x-1)(x+7)
take out another value between -7 and 1 and put it into ^

and finally a value less than -7 and put it into (x-1)(x+7)

and see if they are less than 0

leebux101:
yeah what u did earlier was ryt too..
and the answer is the same in the marking scheme


secondly >> i did square the sides! =( but i dont get it,
can u give a step by step description please! please! =(

leebux101:

--- Quote from: Dumb economist on May 18, 2011, 06:18:31 pm ---and to find the range
just put the values -7 and 1 on a number line

take out any value less than 1 like 0 and put it into (x-1)(x+7)
take out another value between -7 and 1 and put it into ^

and finally a value less than -7 and put it into (x-1)(x+7)

and see if they are less than 0

--- End quote ---
hey i didnt know we could do that... interesting..

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--- Quote from: SkyPilotage on May 18, 2011, 06:17:10 pm ---Actually you solved it correctly the first time...
The least value for modulus of z is where the line from the origin intersets the circle closest to the origin which is somewhere at the centre of the circle.. Check the diagram you drew again.. And isnt the modulus of u is root 2 not 2root2?

--- End quote ---


dude they're not asking for least value of modulus of z
they're asking for modulus of z when argument of z is least

SkyPilotage:

--- Quote from: Dumb economist on May 18, 2011, 06:22:45 pm ---
dude they're not asking for least value of modulus of z
they're asking for modulus of z when argument of z is least


--- End quote ---
which question are you on? ahaha

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