Qualification > Math

[CIE] All Pure Mathematics (P1, P2 and P3) doubts here !

<< < (54/111) > >>

Tohru Kyo Sohma:

--- Quote from: iluvme on May 07, 2011, 11:10:03 pm ---Here you go.

--- End quote ---
thanx alot amii

Tohru Kyo Sohma:
i just have a few more questions...pls pls help me...its;
1. may/june 2009 p1 qns 4 part 2....the answer is 7pi/12....but i cant get it right....can some one show how?
2. oct/nov 2009 p12 qns 5 part 1 ,can someone show me how to solve the inequality?
3. oct/nov 2010 p12 qns 7 part 3....???
4. oct/nov 2010 p13 qns 8 part 2 ????
PLEASE HELP ME...!!!!!EXAM TOMORROW!! :-[

elemis:
Question 1

6 sin(2x) +3 = 0

sin(2x) = -1/2

sin-1(-1/2) = -30, 330, 690, 210 or 570.       I prefer working in degrees then converting to radians at the end.

Dividing all the above answers by 2.

-15, 165, 345,105, 285.

-15 is not in the given range (see question), hence, we ignore it.

The smallest angles is thus 105 degrees. Converting to radians give the correct answer.

Question 2

Part 1 :-  Expanding :

sinx -sin2xcosx +cosx -sinxcos2x

Substitute cos2x for sin2x and sin2x for cos2x. You should get the answer.

Part 2 :-

cos3x = 8sin3x







Solve for x.

Question 3

I'll get back to you on this one.

Tohru Kyo Sohma:

--- Quote from: Ari Ben Canaan on May 08, 2011, 08:48:33 am ---Question 1

6 sin(2x) +3 = 0

sin(2x) = -1/2

sin-1(-1/2) = -30, 330, 690, 210 or 570.       I prefer working in degrees then converting to radians at the end.

Dividing all the above answers by 2.

-15, 165, 345,105, 285.

-15 is not in the given range (see question), hence, we ignore it.

The smallest angles is thus 105 degrees. Converting to radians give the correct answer.

Question 2

Part 1 :-  Expanding :

sinx -sin2xcosx +cosx -sinxcos2x

Substitute cos2x for sin2x and sin2x for cos2x. You should get the answer.

Part 2 :-

cos3x = 8sin3x







Solve for x.

Question 3

I'll get back to you on this one.



--- End quote ---
thanx alot! ;D

SkyPilotage:

--- Quote from: mimiswift on May 08, 2011, 07:25:57 am ---i just have a few more questions...pls pls help me...its;
1. may/june 2009 p1 qns 4 part 2....the answer is 7pi/12....but i cant get it right....can some one show how?
2. oct/nov 2009 p12 qns 5 part 1 ,can someone show me how to solve the inequality?
3. oct/nov 2010 p12 qns 7 part 3....???
4. oct/nov 2010 p13 qns 8 part 2 ????
PLEASE HELP ME...!!!!!EXAM TOMORROW!! :-[

--- End quote ---
Question 3:
Complete the square of f(x) to get (x-2)^2+3 to H(x-2)=(x-2)^2+3----> so H(x) = x^2+3.....
Question 4:
length of PQ is the (length of radius of the arc - height of triangle ) x 2
----> (5-5cos(0.6rad))x2


@ Ari: do you know how marks are distributed on sketches of graphs? (not drawings)

Navigation

[0] Message Index

[#] Next page

[*] Previous page