Qualification > Math
[CIE] All Pure Mathematics (P1, P2 and P3) doubts here !
bulono:
i no but in the mark scheme it is written as (pi)r
http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9709%20-%20Mathematics/9709_s04_ms.pdf
Vin:
because its half the circle?
2(pi) r /2
= (pi) r
bulono:
ohhhhhhhhhhhh...lol...thankxxx
doubtigetastar:
--- Quote from: SkyPilotage on May 06, 2011, 10:32:15 pm ----du/dt=-3 when t=2 soo : a+2b=-3
-maximum value of u is 5.5 so du/dt=0 : a+b=0
So solve the eqns you get b=-3 and a=3
Then integrate du/dt to get u= 3t-1.5t^2+c --->subsitute (1,5.5) to get c=4 -----> so u=3t-1.5t^2+4
Hope it helps...
--- End quote ---
Thanks :)
iluvme:
--- Quote from: Vin on May 06, 2011, 09:51:56 pm ---Don't you complete the square for f(x) and substitute in hg? I think that's the smallest way. :/
--- End quote ---
This was what I did,
hg(x) = f(x)
h(x) = x2+bx+c
h(x-2)= (x-2)2 + b(x-2) +c = x2-4x+7
x2-4x+4+bx-2b+c= x2-4x+7
b=0 c=3
h(x) = x2+3
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