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[CIE] All Pure Mathematics (P1, P2 and P3) doubts here !

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Vin:

--- Quote from: $H00t!N& $t@r on May 01, 2011, 10:02:39 pm ---need help with q 2, 6(ii) and 10 O/N 2010 variant 12

Here is the link: http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9709%20-%20Mathematics/9709_w10_qp_12.pdf

 

--- End quote ---

Q2
Right hand side

tan2x sin2 x  

=tan2x (1 - cos2 x)

=tan2 x - tan2x cos2x

As tanx = sinx / cosx
cos x = sinx/ tanx

=tan2x - tan2x *

=tan2x - sin2x

Vin:

--- Quote from: polltery on May 02, 2011, 04:45:20 am ---the marked one is done! but i need help with the second one.. cant really understand how do i integrate it :/

--- End quote ---

There's a formula to integrate functions of the form (ax + b)n

f(x) = (ax + b)n

if f(x)  = y

y = (ax + b)n





= (ax + b)n+1
   ----------        x
   n + 1  


DO NOT forget to multiply by 1/a

Vin:

--- Quote from: $H00t!N& $t@r on May 01, 2011, 10:02:39 pm ---need help with q 2, 6(ii) and 10 O/N 2010 variant 12

Here is the link: http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9709%20-%20Mathematics/9709_w10_qp_12.pdf

 

--- End quote ---

Q6 ii)

y = kx2 +1   &  y = kx

equate the two to get k = 4 (follow up from the previous- but k2 - 4k = 0 )
equate k=4 in kx2 - kx +1 = 0 to get x = 1/2
equate x = 1/2 in one of the equations to get the y coordinate

Q 10

Expressing h in terms of x

Vol = 4 cm3 (given)

vol of object = x * 0.5x * h
4 = 0.5 * h * x^2
Change the sub. of formula to h to get h = 8/x2

Total Surface area (consider each side and add them up to make things easy)

= 2xh + 2*0.5*xh + 0.5 * x* x + 4/5 x * 5/4 x

solve, and substitute h = 8/x2 to get the desired answer.

ii)

dA/ dx = 1.5 * 2 * x + 24 * -1 * * x -1-1

= 3x - 24/x^2

equate this to zero to obtain the stationary point as 2

d2A/ dx2 = 3 - 24 * -2 * x -2-1

= 3 + 48/x^3

equate x =2 to get 9
since 9 > 0, point of minima

physichemaths:
help me with question j08 question8? anyone?

HUSH1994:
MJ 2010 P13,Q6 part 1,i did AB.BC but in the MS it was AB.CB,how do u know which order do u use?

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