Qualification > Math

Urgent: Maths CIE Stats

<< < (9/22) > >>

Freaked12:

--- Quote from: lana on November 01, 2010, 06:53:48 pm ---another question !! ( sorry !! :P)
(just iv and v)
7 Nine cards, each of a different colour, are to be arranged in a line.
(i) How many different arrangements of the 9 cards are possible?
The 9 cards include a pink card and a green card.
(ii) How many different arrangements do not have the pink card next to the green card?
Consider all possible choices of 3 cards from the 9 cards with the 3 cards being arranged in a line.
(iii) How many different arrangements in total of 3 cards are possible?
(iv) How many of the arrangements of 3 cards in part (iii) contain the pink card?
(v) How many of the arrangements of 3 cards in part (iii) do not have the pink card next to the green
card?
thanks =]

--- End quote ---

We have to start from part iii to continue with part iv and v
a permutation of a set of values is an arrangement of those values into a particular order.
so 9p3=504

iv)We have to assume that the pink card has been chosen in a group of 3 cards so now that group has 2 places remaining
8P2=56
There will be three groups in total which can be made from a group of 9 cards and 56 times 8 cards other th&n the pink can fit in two places of a group in which the pink card has already been chosen.
so we multiply 56 * 3 =168

lana:


thank youu soo soo much that was very helpful
+rep =]

Freaked12:
__ __ 7C1

7C1 __ __

There will be two ways the pink and Green card can shift between themselves as 2!=2
and there are two ways they can stay together

2*2*7=28

504-28=476

Freaked12:
Explained it in a easier way

~Sf staff at your service

lana:

--- Quote from: Requiem on November 01, 2010, 09:30:29 pm ---Explained it in a easier way

~Sf staff at your service

--- End quote ---
aaawww you guys are just amazing thank youu =]

Navigation

[0] Message Index

[#] Next page

[*] Previous page