« previous next »
Pages: [1]   Go Down

Author Topic: physics question related to electricity.  (Read 771 times)

Offline ashwinkandel

  • SF Citizen
  • ***
  • Posts: 144
  • Reputation: 521
physics question related to electricity.
« on: October 25, 2010, 12:30:40 pm »
i m confused with one question.  hope someone posts the solution with reasoning. the question is uploaded here::
http://www.mediafire.com/?p02cor3wp44h9hj
Logged

Offline Chingoo

  • Prima Donna u__u
  • SF Senior Citizen
  • *****
  • Posts: 798
  • Reputation: 65535
  • Gender: Female
  • RAWR
Re: physics question related to electricity.
« Reply #1 on: October 25, 2010, 02:41:20 pm »
6(a) Plate Y is positively charged, as weight acts in downward direction and a repulsive force of equal magnitude but opposite direction between the positively charged plate and positive particle causes the particle to be stationary.
6(b)(i) E = V/d (where E = Electric Field Strength, V = Potential Difference, d = Separation between Plates)
                   E = (630)/(0.75 x 10-2)
                   E = 8.4 x 104 NC-1 or Vm-1
6(b)(ii) F = ma (where F = Force Acting on the Particle, m = Mass of the Particle, a = Acceleration due to Gravity)
                   F = (9.6 x 10-15)(9.81)
                   F = 9.418 x 10-14 N ~ 9.42 x 10-14 N
                   E = F/Q (where E = Electric Field Strength, F = Force Acting on the Particle, Q = Charge on the Particle)
                   Q = F/E
                   Q = (9.418 x 10-14)/(8.4 x 104)
                   Q = 1.121 x 10-14 C ~ 1.12 x 10-14 C

Feel free to ask for further explanation ^_^
Logged
All that is on earth will perish:
But will abide (forever) the Face of thy Lord--full of Majesty, Bounty & Honor.
Then which of the favors of your Lord will ye deny?

Qura'n, Chapter 55: The Beneficent, Verses 26-28

Offline Deadly_king

  • <<Th3 BO$$>>
  • Global Moderator
  • SF Farseer
  • *****
  • Posts: 3391
  • Reputation: 65078
  • Gender: Male
  • Hard work ALWAYS pays off.........just be patient!
    • @pump_upp - best crypto pumps on telegram !
Re: physics question related to electricity.
« Reply #2 on: October 26, 2010, 05:04:23 am »
Quote from: Chingoo on October 25, 2010, 02:41:20 pm
6(a) Plate Y is positively charged, as weight acts in downward direction and a repulsive force of equal magnitude but opposite direction between the positively charged plate and positive particle causes the particle to be stationary.
6(b)(i) E = V/d (where E = Electric Field Strength, V = Potential Difference, d = Separation between Plates)
                   E = (630)/(0.75 x 10-2)
                   E = 8.4 x 104 NC-1 or Vm-1
6(b)(ii) F = ma (where F = Force Acting on the Particle, m = Mass of the Particle, a = Acceleration due to Gravity)
                   F = (9.6 x 10-15)(9.81)
                   F = 9.418 x 10-14 N ~ 9.42 x 10-14 N
                   E = F/Q (where E = Electric Field Strength, F = Force Acting on the Particle, Q = Charge on the Particle)
                   Q = F/E
                   Q = (9.418 x 10-14)/(8.4 x 104)
                   Q = 1.121 x 10-14 C ~ 1.12 x 10-14 C

Feel free to ask for further explanation ^_^

Nice piece of work Chingoo :)

Thanks for your help ;)
Logged
Pages: [1]   Go Up
« previous next »