Qualification > Queries
AS maths paper 13 Oct/nov 2010 discussion
Fatema:
--- Quote from: cs on October 15, 2010, 12:29:26 am ---It was hard for the most of the people in my school, i manage to do them after second round, but i missed out the "show" the real roots part in the last question before finding a and b, Do you remember your answer for the area in the last question..? and the circular measure part?
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well. i couldnt do the circular measure part. found it difficult. as for area i dnt remember the ans.
the a and b i found but dnt remember if i ever showd the real roots or wat.
wat country are u from?
cs:
--- Quote from: Fatema on October 15, 2010, 05:05:18 am ---well. i couldnt do the circular measure part. found it difficult. as for area i dnt remember the ans.
the a and b i found but dnt remember if i ever showd the real roots or wat.
wat country are u from?
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I am from Brunei, i got 2.25 for the area, and a is 1 b is 2..? my friend told me that the question ask to show that a and b are real roots of curve, which you need to substitute both equation to get the equation they provided which is x^6 something something.. i missed out that part although i did it in my mind.. the circular measure part, i got it, but i am not sure if its correct, i got 7.5 for the area of shaded region though..
Fatema:
--- Quote from: cs on October 15, 2010, 05:35:40 am ---I am from Brunei, i got 2.25 for the area, and a is 1 b is 2..? my friend told me that the question ask to show that a and b are real roots of curve, which you need to substitute both equation to get the equation they provided which is x^6 something something.. i missed out that part although i did it in my mind.. the circular measure part, i got it, but i am not sure if its correct, i got 7.5 for the area of shaded region though..
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oh yah i remember dng that part. it was x^6+x^3.... if m not mistaken. yes i got the values 1 and 2 but dnt remember which is which. wat ans did u get for the sketching of graph the y= 2 sin x and u were gvn the other part where u hv 2 write the eqn of straight line gvn that 2pi sinx = -ve pi x (sumthing liker that) dnt remember the qn clearly
cs:
--- Quote from: Fatema on October 15, 2010, 06:51:23 am ---oh yah i remember dng that part. it was x^6+x^3.... if m not mistaken. yes i got the values 1 and 2 but dnt remember which is which. wat ans did u get for the sketching of graph the y= 2 sin x and u were gvn the other part where u hv 2 write the eqn of straight line gvn that 2pi sinx = -ve pi x (sumthing liker that) dnt remember the qn clearly
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I don't know the correct answer but i wrote 3 roots, what about you? cos it cuts at 3 place, the equation i put, y= -(1 over pie) x + 1 ...i divide everything by pie
lana:
--- Quote from: Deadly_king on October 15, 2010, 04:49:23 am ---Yeah...........am having a bad time with physics as well :(
These links may be helpful to clear some of your doubts :
http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html
http://www.astarmathsandphysics.com/
http://www.s-cool.co.uk/alevel.html
Yeah......the answer was 11/12 pie ;)
Am afraid to tell you that but the answer would be 2.88 without pie.
Though your method (pie x integration of [y12 - y22]) was correct.
Initially I did it the same way you did but got a negative value as answer. So I decided to do it step by step and I finally obtained the correct answer.(according to me and my friends)
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Thank you so much that was very helpful =]
good luck with everything =]
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