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Math P2 May/Jun 1999 HELP !!!

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Q80BOY:
IGCSE (CIE) Mathematics Paper 2 May/June 1999

(i attached the paper)

Page 5, Question 11 (Done)

Page 6, Question 14, Part (a), Section (ii) (Done)

Page 8, Question 18, Part (b), Section (i) (Done)

Special thanks to Zara for helping me with the questions

zara:
page 5, q 11......so draw a tangent to the point where x=2..n then take ny two points on it and then with the help of its co-ordinates calculate the gradient....gradient=(y2-y1)/(x2-x1)


page 6, q14.....1st calculate f(-5)=2(-5)+1=-9
            then,,,g(-9)=(-92)+3=84
                            note: its -9*-9=81

ill post the answer to ur last ques in a few mins.... :)
                                             

zara:
answer to ur last ques (i)>>>1st vll calculate the value of k

>>>T=kH
>>>-5=k500
>>>k=-0.01

then,,
>>>T=-0.01H
>>>-18=-0.01H
>>>H=1800m

therefore,,,height of the top of the mountain above sea level =1800+2500=4300m

note: v added 2500 bcz the ques was height above sea level nt above base camp

plz chk the answer with the mark scheme,,,,n if its rong plz lemme kno...
Thanks.. :)

Q80BOY:

--- Quote from: zara on May 07, 2009, 03:33:12 pm ---answer to ur last ques (i)>>>1st vll calculate the value of k

>>>T=kH
>>>-5=k500
>>>k=-0.01

then,,
>>>T=-0.01H
>>>-18=-0.01H
>>>H=1800m

therefore,,,height of the top of the mountain above sea level =1800+2500=4300m

note: v added 2500 bcz the ques was height above sea level nt above base camp

plz chk the answer with the mark scheme,,,,n if its rong plz lemme kno...
Thanks.. :)

--- End quote ---


Thanks for the help on the first two questions + rep (do u mind drawing the tangent on the image above, i dunno how to drow it) :-[

and ur answer to Q18 is wrong, the m/s says its 4300  ??? wht did they get it from ?? and k = -0.01

zara:
even i got the answer as 4300m....plz chk again above...
n how they got -0.01 is also specified in m working above...
just read m post once mor n ull get it... ;)

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