Qualification > Math

CIE AS P1 Math Problem M/J 2010

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missbeautiful789:
Oh shucks...i could have used that quadrant angle thingy majig.
trig bones.

Thanks guys, -  thank you Asif 

S.M.A.T:

--- Quote from: Deadly_king on October 11, 2010, 05:58:44 pm ---+ rep Asif

This question........especially the third one was haunting my mind as well ;)

--- End quote ---

Thanks for +rep :)
i was also stuck with the third one but after thinking for a while i found out how to do it ;D

Garfield:thank U ;D
missbeautiful789:U welcome :D
 

rocker:
Another method
Consider the right angle triangle with x angle.let triangle be ABC WITH AC hypotenuse.THE
Tan X =BC/AB
k=Bc/AB
Bc=kAB
how find Ac by using paythagrous therom which gives Ac^2=Bc^2+AB^2
and AC=bc(k^2+1)^(1/2)
now use sIN x=BC/Ac
put value of Ac and Bc=KAB it will give you
sin x=K/(K^2+1)^1/2
thank you
ITseems like complicated but try by drying triangle.

Deadly_king:

--- Quote from: rocker on October 12, 2010, 08:08:40 am ---Another method
Consider the right angle triangle with x angle.let triangle be ABC WITH AC hypotenuse.THE
Tan X =BC/AB
k=Bc/AB
Bc=kAB
how find Ac by using paythagrous therom which gives Ac^2=Bc^2+AB^2
and AC=bc(k^2+1)^(1/2)
now use sIN x=BC/Ac
put value of Ac and Bc=KAB it will give you
sin x=K/(K^2+1)^1/2
thank you
ITseems like complicated but try by drying triangle.

--- End quote ---

yeah.......I got it :)

It's indeed easier and simpler ;)

+rep to you as well

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