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Mechanics Question

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S.M.A.T:

--- Quote from: Dania on October 16, 2010, 11:45:27 pm ---A ball is projected from a point O on the edge of a vertical cliff. The horizontal and vertically upward components of the initial velocity are 7ms-1 and 21ms-1 respectively. At the time t seconds after the projection the ball is at the point (x,y) referred to horizontal and vertically upward axes through O. Air resistance may be neglected.

(i) Express x and y in terms of t, and hence show that y= 3x- 0.1x2

The ball hits the sea at a point which is 25m below the level of O.

(ii) Find the horizontal distance between the cliff and the point where the ball hits the sea.

--- End quote ---

(i)  x=7t(horizontal velocity always remain  constant so the formula used is s=vt)
      y=21t-0.5gt2(s=ut+0.5at2)
    
      t=(x/7)
        
      y=21t-0.5gt2
      y=21(x/7) -0.5g(x/7) 2
      y=3x-0.1x2
(ii) y=-25(because the question said y is vertically upward axes through O the ball hits below O so negative 25)
     3x-0.1x2=-25
    0.1x2-3x-25=0
    solving this equation we get
     x=36.8m

   

Arthur Bon Zavi:

--- Quote from: asiftasfiq93 on October 17, 2010, 02:48:12 am ---(i)  x=7t(horizontal velocity always remain  constant so the formula used is s=vt)
      y=21t-0.5gt2(s=ut+0.5at2)
    
      t=(x/7)
        
      y=21t-0.5gt2
      y=21(x/7) -0.5g(x/7) 2
      y=3x-0.1x2
(ii) y=-25(because the question said y is vertically upward axes through O the ball hits below O so negative 25)
     3x-0.1x2=-25
    0.1x2-3x-25=0
    solving this equation we get
     x=36.8m

   


--- End quote ---

Have You Completed yous A Levels? :D

S.M.A.T:

--- Quote from: Ancestor on October 17, 2010, 07:25:34 am ---Have You Completed yous A Levels? :D

--- End quote ---

no,still doing my A2.:)

Arthur Bon Zavi:

--- Quote from: asiftasfiq93 on October 18, 2010, 10:55:13 am ---no,still doing my A2.:)

--- End quote ---

Well Then Go Ahead!  8)

astarmathsandphysics:
they found the angle between south and the 6N force and resolved vertically

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