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ALL CIE PHYSICS DOUBTS HERE !!!

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$!$RatJumper$!$:

--- Quote from: Hypernova on November 13, 2010, 11:14:25 pm ---Q37)

The potentiometer!!

In this circuit,

E2 = E1 x resistance of XT
            resistance of XY + R


since the galvanometer is reading a null result, we know that the pd across XT is equal to E2.
The galvanometer is basically an ammeter. 0 amps means 0 p.d which means that the p.d across XT exactly nullifies the emf produced by E2

So we know the length of XT. All we need is E2 and divide it by the length to find its pd per length.

--- End quote ---

Thank you that helped :)


--- Quote from: TJ-56 on November 13, 2010, 11:10:08 pm ---Well the original equation is
u1 - u2 = - (v1 - v2)  Which is derived by using both the principle of conservation of momentum and energy, where it is assumed all directions are the same (for example both to the left before and both with velocities to the left after)
since u1 and u2 are in different direction , its now u1 -  -u2, which is u1 + u2
and on the right hand side, -(v1 -v2) which is v2 - v1
Thats all there is to it i guess, hope that cleared it up.


--- End quote ---

Many thanks that helped a lot :)

+rep both

$!$RatJumper$!$:
S08 Q 24, 29, 32, 34 please
:)

thecandydoll:
W09 VARIANT 11 P1 PHYSICS.
Q15

thecandydoll:
may/june 2009
20/21

I dont get it :(

thecandydoll:
wrong questions.

http://www.xtremepapers.net/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_w09_qp_11.pdf


Q15

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