Qualification > Sciences
ALL CIE PHYSICS DOUBTS HERE !!!
Deadly_king:
--- Quote from: Dania on November 10, 2010, 02:29:21 pm ---Refer to the attachments
Look at the paper, for the full question. [Question no. 4]
Thanks in advance.
--- End quote ---
I assume that you got the answers for part (a)(ii).
You should then use the two answers namely R = L/A and E = WL/Ae.
As you can note, you have been given R = 0.44, = 9.2 x 10-8, W = 34 and e = 7.7 x 10-4 and you're asked to find the young modulus E.
But according to the equation you cannot find it since you don't have L and A. However you can use the 1st equation to find it. ;)
1st equation : R = L/A can also be written as R/ = L/A
Now you replace it in the second equation.
E = W/e x L/A. Since L/A = R/, this implies E = W/e x R/ which therefore results in E = WR/e
Hope it helps :)
Deadly_king:
--- Quote from: $!$RatJumper$!$ on November 10, 2010, 03:04:23 pm ---W09 P22 Q5b
Thank you :)
--- End quote ---
Nov 09 p22
(b) There is no calculation here.
You should have guessed that by the number of marks allocated for the question.
It said state; which means it's pretty obvious from the drawing.
First thing : You should realize that both X and Y are equidistant from a node. Therefore the phase difference should be pie rad or 180o.
Furthermore it can also be noted that X and Y are in antiphase ( One is above while the other one is below). If Y was 1/8L to the right of P, then Y would have been at a phase difference of 180o but in phase. ;)
Hope it helps :)
TJ-56:
Can sumone pls explain s10 P2 Q7 (b) (ii)
thank you
$!$RatJumper$!$:
--- Quote from: Deadly_king on November 10, 2010, 03:43:14 pm ---Nov 09 p22
(b) There is no calculation here.
You should have guessed that by the number of marks allocated for the question.
It said state; which means it's pretty obvious from the drawing.
First thing : You should realize that both X and Y are equidistant from a node. Therefore the phase difference should be pie rad or 180o.
Furthermore it can also be noted that X and Y are in antiphase ( One is above while the other one is below). If Y was 1/8L to the right of P, then Y would have been at a phase difference of 180o but in phase. ;)
Hope it helps :)
--- End quote ---
Hmm im still confused. What i thought was that since X was 1/8th of the wavelength away from the start and Y was 1/8th of the wavelength away from the end, they would each be 45 degrees away from the start and end. Thus 360-(45*2) = 270 degrees.
So what if point X was at the end to the left (by the oscillator) and point Y was at the end to the right (by P), what would the phase diff be then?
:(
Dania:
--- Quote from: Deadly_king on November 10, 2010, 03:12:56 pm ---I assume that you got the answers for part (a)(ii).
You should then use the two answers namely R = L/A and E = WL/Ae.
As you can note, you have been given R = 0.44, = 9.2 x 10-8, W = 34 and e = 7.7 x 10-4 and you're asked to find the young modulus E.
But according to the equation you cannot find it since you don't have L and A. However you can use the 1st equation to find it. ;)
1st equation : R = L/A can also be written as R/ = L/A
Now you replace it in the second equation.
E = W/e x L/A. Since L/A = R/, this implies E = W/e x R/ which therefore results in E = WR/e
Hope it helps :)
--- End quote ---
Thanks! Got it.
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