Qualification > Sciences
ALL CIE PHYSICS DOUBTS HERE !!!
$!$RatJumper$!$:
--- Quote from: TJ-56 on November 09, 2010, 11:43:34 am ---say the maximum amp of the given wave is 2 (taking each 5 small blocks as 1)
then we have:
I(new)/I = A(new)²/A²
0.5I/I = A(new)²/(2A)²
Making A(new) ² the subject gives us = sqr root(2A²)
= sqr root(2) * A
which is 1.4 (the new amplitude)
--- End quote ---
Thank you so much :) i finally understand how to do it :) just to make sure can u please draw it out again? thank you. and im cheking out the other answers for my other question now. thankx again! +rep
$!$RatJumper$!$:
--- Quote from: TJ-56 on November 09, 2010, 11:30:21 am ---(b) 32.4 cm is the distance between 1 nodes, i.e. half the distance of a complete wavelength. v=f * lambda
frequencey is stated, 512 Hz
Lambda= 32.4*2 *10^-2 (im meters)
so 512*64.8 * 10^-2 = 330 m\s
(c) the exact distance of the antinode is half 32.4
So 32.4/2 = 16.2
So the antinode is 16.2 cm above the surface of water in the tube on the left.
As 15.7 cm is the length of the column of air INSIDE the tube, then 16.2-15.7 is the length of air above the where the antinode is located.
Hope that was helpful
--- End quote ---
that was very helpful thankx! though just a question.. why did you only draw half a wavelength in the tube? are there certain rules as in how many wavelengths to draw when drawing stationary waves
TJ-56:
--- Quote from: $!$RatJumper$!$ on November 09, 2010, 12:23:08 pm ---Thank you so much :) i finally understand how to do it :) just to make sure can u please draw it out again? thank you. and im cheking out the other answers for my other question now. thankx again! +rep
--- End quote ---
There u go
$!$RatJumper$!$:
gr8 stuff :) thankx.. could you please answer my other question aswell about the stationary waves
TJ-56:
--- Quote from: $!$RatJumper$!$ on November 09, 2010, 12:47:39 pm ---gr8 stuff :) thankx.. could you please answer my other question aswell about the stationary waves
--- End quote ---
I didnt understand ur question, the qp though implies that only half a wavelength should be drawn, (difference between 2 loud sounds)
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