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ALL CIE PHYSICS DOUBTS HERE !!!

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$!$RatJumper$!$:

--- Quote from: TJ-56 on November 07, 2010, 06:57:52 pm ---Can someone solve s07 qp2 q4 (d) both parts, literally driving me crazy, and if u can pls post the vector diagram,
thanx for the help

--- End quote ---

Hope this helps :)

TJ-56:
thanx
+rep

Hypernova:

--- Quote from: Deadly_king on November 07, 2010, 03:42:21 pm ---The level of water will rise.

But we may not note this rise due to the large surface area covered by the pond, even if the pond is very small. ;)

The volume displaced by the anchor upon sinking may be negligible compared to the total volume of water in the pond.

--- End quote ---

wait a sec.

First the anchor is on the boat. It exerts a downward force on the boat, forcing the boat down, so displacing alot of water.

When the anchor is released, less of the ship is in the water therefore less water diplacement. The volume diplaced by the anchor is small.

The higher the water displacement, the higher the water level.

Since water displacement decreased the water level should also decrease.

Imagine yourself in a bathtub. Imagine that the anchor is on you, you will go deeper into the water, the water will rise. when the anchor is released, less of you will be in the water, so the water level will decrease.

astarmathsandphysics:

--- Quote from: SpongeBob on November 07, 2010, 05:02:55 pm ---If anyone could help me with this? (:



--- End quote ---

Need part i) of the question. :D

astarmathsandphysics:
If the anchor doesnt reach the bottom the overall water level will not change cos the weight of water displaced equals weight of boat + weight of anchor.
If the anchor hits the bottom then archimedes principle only applies to the boat. The weight of water displaced equals the weight of the boat only, so less water is displaced and the water level falls.

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