Qualification > Sciences
ALL CIE PHYSICS DOUBTS HERE !!!
Deadly_king:
--- Quote from: TJ-56 on November 05, 2010, 09:38:09 pm ---Can sumone help me with diagrams in nov 2003 qp2, the first one is q3 (c) (i) just wanna make sure if its right and explain if you can pls,
the second one is q5 (c) why isn't it a straight line from origin, why does it have a curve as it says on the mark scheme?
thanks so much for any help in advance
--- End quote ---
Nov 03 p2
3.(c)(i) In both strings the tension is directed towards the pulley. But I don't know how to explain it. :-[
5.(c) Hmm...........first you should realize that it is a graph of velocity against distance from A.
Hence the gradient will be velocity/distance which is also equal to 1/time.
Therefore as the electron moves from A to B, time is increasing.
Since gradient = 1/time, an increase in time will lead to a decrease in gradient.
But velocity of the electron will be increasing due to the force of attraction from plate B and the force of repulsion from plate A.
Thus the graph should indicate an increase in speed while the gradient will be decreasing. This is why a curve is drawn instead of a straight line. ;)
Hope it helps :)
$!$RatJumper$!$:
--- Quote from: Deadly_king on November 06, 2010, 05:09:04 am ---Yeah, I understand what you mean. Once it was rather complicated for me too. ;)
You should know this formula => Phase angle = 2(pie)/lambda
This formula applies when you have a graph of x against wavelength(lambda). Since in this case the graph is x against time(t), we can change the formula to => Phase angle = 2(pie)/T, where T is the period of oscillation and is the time difference.
It has been said that both waves have the same waveform, which implies same wavelength and same period. The only difference is that one would lead the other.
Take 2(pie) as 360o since the phase angle has been given in degrees and not radians.
Hence 60o = 2(180)/3 ---> = 0.5s
Therefore the new wave will lag behind by 0.5s, i.e it will have its first maximum at 0.5s and the first minimum at 2s.
Hope you get it. :)
Am sorry but I don't have any specific sites for this topic, but here are some links which a member has been so kind to look for us. :D
--- End quote ---
Excellent info. Thank you! +rep
$!$RatJumper$!$:
What is the difference between the equations:
D*n*(lambda) / d
D*(lambda) / d
Dania:
Do you mind drawing it out for me and uploading the pic? I get what you're saying. But I'm finding it hard to draw it. Thanks.
Deadly_king:
--- Quote from: Dania on November 06, 2010, 09:45:21 am ---Do you mind drawing it out for me and uploading the pic? I get what you're saying. But I'm finding it hard to draw it. Thanks.
--- End quote ---
Am sorry but I don't have a scanner :-[
Nevertheless I'll see what i can do for you.
Navigation
[0] Message Index
[#] Next page
[*] Previous page
Go to full version