Qualification > Sciences
ALL CIE PHYSICS DOUBTS HERE !!!
SkyPilotage:
--- Quote from: mathy on April 14, 2012, 09:45:43 am ---jazakAllah khairen!!!!!!!!!!!
ok can u please explain me the reason for Q6 b)..why is the first (top one) like that? what;s the relation ship to be used?
and for 6 a for j06y, wud u plz explain, me the direction of B....like how did u get it downwards?
By the way Thanks a lot!!!!!!! it helped me...:)
P.S. I tried quoting the post but was unable to do..?! i dunno y?? :s
--- End quote ---
June 2005
Question 6 B)
I) Magnetic Flux is proportional to the change in current so its the same as the current graph given in the question.
II) The e.m.f is the negative of the gradient of the magnetic flux graph by Faraday Lenz Law that Emf= - N(flux)/time so it is the negative of the rate of change of flux. So when the graph of Phi is steepest, emf is maximum
June 2006
Question 6 A)
The magnetic field around point Y due to XY is circular, Therefore at Point Q, the direction of the magnitic field is tangential to the magnetic field at Y. Which is downwards.
Hope it helped you, brother!
--------If you need to quote, just click quote which is at the top right of that post. Then you can type what you want under it :)-------------
mathy:
--- Quote from: SkyPilotage on April 14, 2012, 10:12:46 am ---June 2005
Question 6 B)
I) Magnetic Flux is proportional to the change in current so its the same as the current graph given in the question.
II) The e.m.f is the negative of the gradient of the magnetic flux graph by Faraday Lenz Law that Emf= - N(flux)/time so it is the negative of the rate of change of flux. So when the graph of Phi is steepest, emf is maximum
June 2006
Question 6 A)
The magnetic field around point Y due to XY is circular, Therefore at Point Q, the direction of the magnitic field is tangential to the magnetic field at Y. Which is downwards.
Hope it helped you, brother!
--------If you need to quote, just click quote which is at the top right of that post. Then you can type what you want under it :)-------------
--- End quote ---
It definitely did... :) JazakAllah khairen!! :)
thanks a lott!!!!!!
and By the way I did know how to quote..I guess, I had the quick reply feature on, bcoz of which that wasn't working, I turned it off, and it works now.. :D
SkyPilotage:
Im very glad to help! Feel free to post more doubts!
What do you guys think about why the shock waves frequency has to be higher than the natural frequency of the seismometer?
Physics09:
Reply urgently please!
http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Physics%20(9702)/9702_s11_qp_11.pdf
MCQs 4,9,10,13 and 14
Thank you!
raamishstudent:
4C take the amplitude of the crest not the whole wave and multiply it by 4. The answer should be 1.5 * 4 = 6
9D formula will be m2v2 for momentum after collision so (m+m)v = 2mv. K.e energy will be 1/2mv2 * 1/2mv2 = mv2
10D direction is changing so negative sign. So change will be -mv -(mv) = -2mv
And i dont know how to do 13 and 14 so plzz somebdy do them :)))
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