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physics help needed........plz

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ashwinkandel:
The mass of a cube of aluminium is found to be 580 g with an uncertainty in the measurement of 10 g. Each side of the cube has a length of (6.0 ± 0.1) cm.
Calculate the density of aluminium with its uncertainty. Express your answer to an appropriate number of significant figures.

density= ......................±................... g cm-3

elemis:
Whats the answer ?

elemis:
equation 1

adding the fractional uncertainties :equation 2

Hence, multiplying 1 and 2 gives an absolute uncertainty of 0.2

Therefore, ans =

Deadly_king:

--- Quote from: ashwinkandel on October 02, 2010, 02:18:31 pm ---The mass of a cube of aluminium is found to be 580 g with an uncertainty in the measurement of 10 g. Each side of the cube has a length of (6.0 ± 0.1) cm.
Calculate the density of aluminium with its uncertainty. Express your answer to an appropriate number of significant figures.

density= ......................±................... g cm-3

--- End quote ---

hey that's fro, June 09 p2, right??

Anyway it's not that difficult. Let me get this clear for you.

Density = Mass / Volume ---> density = 580/63 = 2.685

Volume of cube = l3

Therefore density = m/l3

Delta D/density * 100 = delta m/mass *100 + 3deltaL/Length * 100

Delta D = [(10/580 * 100) + (3*0.1/6 *100) ] * 2.685/100 =0.18

Since all the values given were correct to 2 sf, your answer should be correct to 2sf.

Hence answer is 2.7  +- 0.2 gcm-3

elemis:
I got there before you :P

Good work man ;)

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