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Need help on CIE Chemistry Paper 5!

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ashish:

--- Quote from: moon on October 17, 2010, 12:38:16 pm ---Q3(d)

you have to work out the molecular formula let say your mean value for Cu was 2.00

element  mass    Ar          mole         /simplest
O           1.00    16.0        0.0625        1.98  =2
Cu          2.00    63.5        0.0315       1

Copper (I) oxide
CuO2

hmm it is a fictitious value :D just replace yours and do the calculation



How did u get an average 2??? my average is 3.983 so the formula of copper oxide is CuO PLZ help..... thanks in advance





--- End quote ---

ashish:
here is your answer

element  mass    Ar          mole         /simplest
O           1.00    16.0        0.0625        1.00
Cu         3.983   63.5       0.0627          1.00

answer: CuO


Deadly_king:

--- Quote from: moon on October 17, 2010, 12:44:36 pm ---what is the volume of water do we have to use???????

Thanx a lot for ur help..

--- End quote ---

This will depend.

Example :
1) First experiment you used 50cm3 of a known concentration of solution.
2) Second experiment you are asked to use 30cm3 of the same solution. Since you need to keep total volume constant(50cm3), add 20cm3 of water ;)

Anytime :)

moon:

--- Quote from: ashish on October 17, 2010, 12:57:10 pm ---here is your answer

element  mass    Ar          mole         /simplest
O           1.00    16.0        0.0625        1.00
Cu         3.983   63.5       0.0627          1.00

answer: CuO




--- End quote ---

which value is a fictitious value??? mine or yours

moon:

--- Quote from: Deadly_king on October 17, 2010, 01:09:31 pm ---This will depend.

Example :
1) First experiment you used 50cm3 of a known concentration of solution.
2) Second experiment you are asked to use 30cm3 of the same solution. Since you need to keep total volume constant(50cm3), add 20cm3 of water ;)

Anytime :)

--- End quote ---
did we assume that total volume will be 50cm3 in experiment????
Ur explanation is wonderful. You are doing a great job...thank u very much :)

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